Wave optics (interference, diffraction and polarization) is a high-yield chapter for CBSE Class 12 and for competitive exams (JEE/NEET) because it tests both conceptual understanding (phase, coherence, boundary phase reversals) and quantitative skills (fringe width, resolving power, diffraction minima). Mastery of these topics helps in solving multi-step problems where simple formula recall is not enough—students must combine geometry, phase relations and approximations.
This quiz emphasizes analysis and exam-style traps: assertion–reason reasoning, graph/data interpretation, numerical calculations with unit conversions, and conceptual misconceptions (e.g., phase change on reflection, missing orders, role of source size). Work through each problem analytically; rough approximations and sign/phase thinking are often the key to correct answers.
15
Minutes
10
Questions
1 / -0
Marking
Q1. In Young's double-slit experiment the slit separation is and the screen is at distance . Monochromatic light of wavelength is used. A thin transparent sheet of refractive index and thickness is introduced in front of one slit. By how many fringe widths does the central bright fringe shift on the screen?
Q2. A single slit is illuminated by monochromatic light of wavelength . On a screen at distance the width of the central diffraction maximum (distance between the first minima) is measured to be . Using small-angle approximations, the slit width is approximately:
Q3. An oil film of refractive index coats a glass substrate (). Light is incident normally from air. Considering phase changes on reflection, the condition for constructive interference in the light reflected from the film is:
Q4. In the combined interference–diffraction pattern of two identical slits (each of width and centre separation ) it is observed that every third interference maximum (i.e., ) is missing from the observed fringes. Assuming normal incidence, the ratio is:
Q5. Assertion (A): If two narrow slits are illuminated by an extended source of finite width, the interference fringes disappear when the source width exceeds a certain limit.
Reason (R): This happens because temporal coherence of the source decreases as the source width increases.
Both A and R are true and R is the correct explanation of A.
Both A and R are true but R is not the correct explanation of A.
A is true but R is false.
A is false but R is true.
Q6. Two closely spaced sodium lines at wavelengths and are to be resolved using the second order () of a diffraction grating. Using the Rayleigh resolving power (where is the number of illuminated slits), the minimum number of slits required is approximately:
Q7. The normalized intensity distribution of single-slit diffraction shows the first minima at an angular position . If the incident light has wavelength , the slit width is approximately (use and small-angle approximation):
Q8. Unpolarized light of intensity is incident on three ideal polarizers placed in series. The transmission axis of the first polarizer is vertical, the second's axis is at to the first, and the third's axis is at to the first. The intensity transmitted through all three polarizers is:
Q9. Assertion (A): In Newton's rings observed in reflected light using a plano-convex lens on a plane glass plate the central spot is dark.
Reason (R): At the point of contact (centre) the optical path difference between the two reflected rays is zero.
Both A and R are true and R is the correct explanation of A.
Both A and R are true but R is not the correct explanation of A.
A is true but R is false.
A is false but R is true.
Q10. Two point sources separated by angular separation are to be just resolved at wavelength by a telescope with a circular aperture. Using the Rayleigh criterion , the minimum aperture diameter required is approximately: