The d- and f-block elements chapter is essential because it links electronic configurations with observable properties such as magnetic moment, colour (d–d transitions), oxidation states, ligand-field effects, and special behaviours like Jahn–Teller distortions. In CBSE and competitive exams, conceptual clarity on high-spin/low-spin states, CFSE, spin-only moments, and lanthanide trends is directly tested through numerical and reasoning-based MCQs.
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Marking
Q1. Among the following metal ions, which will have the largest (most exothermic) molar enthalpy of hydration? (Use approximate relation , where is ionic charge and the ionic radius.)
Q2. Using the spin‑only formula (where is number of unpaired electrons), which statement correctly compares the effective magnetic moments of and ?
Both complexes are diamagnetic (both )
Both complexes are high‑spin with
Q3. For an octahedral complex of a 3d metal with electronic configuration , if the octahedral splitting energy is (pairing energy ), what is the most likely ‑orbital occupancy and number of unpaired electrons?
High‑spin: , 3 unpaired electrons
Low‑spin: , 1 unpaired electron
Low‑spin: , 0 unpaired electrons
High‑spin: , 4 unpaired electrons
Q4. An octahedral complex of a ion has . Predict the spin state, number of unpaired electrons and whether a strong Jahn–Teller distortion is expected.
High‑spin , 4 unpaired electrons; strong Jahn–Teller distortion expected
Low‑spin , 2 unpaired electrons; strong Jahn–Teller distortion expected
High‑spin , 4 unpaired electrons; no Jahn–Teller distortion
Low‑spin , 2 unpaired electrons; no strong Jahn–Teller distortion
Q5. Which statement correctly describes and in terms of spin state, spin-only magnetic moment and relative d–d absorption energy?
is high-spin (, four unpaired electrons, ) and shows d–d absorption at lower energy (longer wavelength) than ; is low-spin (diamagnetic) because CN is a strong-field ligand.
is high-spin with ; is low-spin (diamagnetic); however shows d–d absorption at lower energy (longer wavelength) than the aqua complex.
is high-spin; is also high-spin and paramagnetic; hence the CN complex shows d–d absorption at lower energy than the aqua complex.
is high-spin but with ; is low-spin (diamagnetic); and the CN complex absorbs at higher energy than the aqua complex.
Q6. Calculate the spin-only magnetic moment (in Bohr magneton) of (high-spin). Use where is the number of unpaired electrons.
Q7. For an octahedral complex the pairing energy is and the octahedral splitting is . Which spin state is energetically favoured and by what energy (in kJ mol)? (Use .)
Low-spin favoured by
Low-spin favoured by
High-spin favoured by
High-spin favoured by
Q8. and are isoelectronic () and form octahedral complexes with identical ligands. Which statement correctly compares crystal field splitting and metal–ligand (M–L) bond lengths?
The complex has larger and shorter M–L bonds.
Both complexes have the same and identical M–L bond lengths.
The complex has larger and shorter M–L bonds.
The complex has larger but the complex has shorter M–L bonds.
Q9. Consider octahedral complexes of () and () with identical ligands. Which of the following best describes their ligand field splitting , covalent character and M–L bond lengths?
shows larger , greater covalency and shorter M–L bonds than .
shows larger , greater covalency and shorter M–L bonds than .
Both have identical , but bonds are more covalent and shorter.
has larger yet significantly longer M–L bonds due to screening.
Q10. Which statement correctly describes and in terms of spin state, spin-only magnetic moment and relative d–d absorption energy?
is high-spin (, four unpaired electrons, ) and shows d–d absorption at lower energy (longer wavelength) than ; is low-spin (diamagnetic) because CN is a strong-field ligand.
is high-spin with ; is low-spin (diamagnetic); however shows d–d absorption at lower energy (longer wavelength) than the aqua complex.
is high-spin; is also high-spin and paramagnetic; hence the CN complex shows d–d absorption at lower energy than the aqua complex.
is high-spin but with ; is low-spin (diamagnetic); and the CN complex absorbs at higher energy than the aqua complex.
Q11. Consider the complexes (tetrahedral) and (square planar). Which statement about their magnetic and electronic properties is correct?
is diamagnetic (all electrons paired) and has two unpaired electrons.
is paramagnetic with two unpaired electrons; is diamagnetic (square planar, low-spin).
has four unpaired electrons; has one unpaired electron.
is low-spin and is high-spin .
Q12. For octahedral complexes the crystal field stabilization energy (CFSE) strongly affects ligand substitution lability. Rank the following electronic configurations in order of increasing lability (most inert first): (i) low-spin , (ii) , (iii) , (iv) high-spin .
(iii) > (ii) > (iv) high-spin > (i) low-spin .
(ii) > (i) low-spin > (iii) > (iv) high-spin .
(iv) high-spin > (iii) > (ii) > (i) low-spin .
(i) low-spin > (ii) > (iii) > (iv) high-spin .
Q13. Three lanthanide ions , and are to be separated by fractional crystallization of their oxalates. Which pair will be hardest to separate and why?
and — their ionic radii are very similar due to lanthanide contraction, so oxalate solubilities are nearly the same.
and — a large difference in ionic radii makes them co-precipitate and thus hardest to separate.
and — because is much smaller, it forms very similar oxalate solubility to Nd.
All three pairs are equally difficult to separate by fractional crystallization.
Q14. Which of the following octahedral 3d complexes will exhibit a strong static Jahn–Teller distortion?
Only and (both high-spin ) show strong Jahn–Teller distortion.
Only ( ) shows strong Jahn–Teller distortion.
(high-spin ), (high-spin ) and ( ) all show strong Jahn–Teller distortion.
Jahn–Teller distortions here are weak/dynamic rather than strong and static.
Q15. Octahedral complexes of 4d and 5d transition metals are observed to be low-spin more often than analogous 3d complexes. Which explanation best accounts for this trend?
Only the pairing energy decreases down the series, so electrons pair readily in 4d/5d.
Both the crystal field splitting increases (better metal–ligand overlap of more diffuse 4d/5d orbitals) and the pairing energy decreases, so pairing becomes energetically favourable — hence low-spin states are preferred.
Only the increase in is responsible; pairing energy remains essentially the same.
Predominantly relativistic effects (contraction of orbitals) alone cause low-spin behaviour in 4d/5d complexes.