Haloalkanes and haloarenes are pivotal in organic chemistry because they connect structure (sterics/electronics) to reactivity through SN1/SN2/E1/E2 and SNAr/addition–elimination mechanisms. Board and competitive exams frequently test how ring activation (e.g., nitro groups) and solvent/nucleophile strength control product formation and stereochemistry, so mastering these patterns is essential for scoring confidently.
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Minutes
20
Questions
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Marking
Q1. Which of the following haloalkanes will react fastest with in dry acetone at 25°C by an mechanism?
(2-chloropropane)
(methyl chloride)
(tert‑butyl chloride)
(ethyl chloride)
Q2. Which of the following halobenzenes will undergo nucleophilic aromatic substitution most rapidly with aqueous at 60°C (addition–elimination pathway)?
(chlorobenzene)
‑chloro‑‑nitrobenzene (‑nitrochlorobenzene)
‑chloro‑‑nitrobenzene (‑nitrochlorobenzene)
‑chloro‑‑nitrobenzene (‑nitrochlorobenzene)
Q3. In the free radical chlorination of isobutane the observed product ratio is tertiary chloride : primary chloride = . Using the relation
(where and are numbers of equivalent tertiary and primary H atoms), estimate the relative reactivity of a tertiary H to a primary H. ( for isobutane.)
Q4. Trans‑1‑bromo‑2‑methylcyclohexane is treated with in methanol under conditions. What is the major stereochemical product?
Inversion at C‑1 giving trans‑1‑methoxy‑2‑methylcyclohexane with OMe axial
Retention at C‑1 giving trans‑1‑methoxy‑2‑methylcyclohexane with OMe equatorial
Inversion at C‑1 giving cis‑1‑methoxy‑2‑methylcyclohexane with OMe equatorial
Inversion at C‑1 giving cis‑1‑methoxy‑2‑methylcyclohexane with OMe axial
Q5. Which of the following dichloronitrobenzenes will undergo nucleophilic substitution by in methanol most rapidly (i.e., give fastest via Meisenheimer intermediate)?
‑chloro‑‑dinitrobenzene
‑chloro‑‑dinitrobenzene
‑chloro‑‑dinitrobenzene
‑chloro‑‑dinitrobenzene
Q6. In the SN2 reaction the rate law is . If initially and giving rate , what is the initial rate when is doubled and is reduced to ?
(doubled)
(halved)
(unchanged)
(quadrupled)
Q7. Consider the alkyl bromides (i) (1°), (ii) (2°), (iii) (3°). Each reacts with at 25°C in (A) acetone (polar aprotic) and (B) ethanol (polar protic). On changing solvent from acetone to ethanol, how does the rate of nucleophilic substitution by change for these substrates?
Rate increases for all three substrates.
Rate decreases for all three substrates.
Rate decreases for (i) and (ii), but increases for (iii).
Rate decreases only for (i); increases for (ii) and (iii).
Q8. When -1-bromo-1-phenylethane, i.e. , reacts with (25°C) in (i) ethanol and (ii) DMSO, which stereochemical outcome is expected in each solvent and why?
In ethanol: nearly racemic product (SN1 predominates); in DMSO: predominantly inverted enantiomer (SN2 predominates).
In ethanol: predominantly inverted enantiomer (SN2); in DMSO: racemic product (SN1).
Both solvents give racemic product due to rapid benzylic carbocation formation in both media.
Both solvents give retention of configuration because the phenyl ring participates as a neighbouring group.
Q9. Which of the following best explains why -chloro--dinitrobenzene undergoes nucleophilic aromatic substitution with methoxide () at room temperature, whereas chlorobenzene requires very harsh conditions (e.g., , high temperature) to substitute?
The C–Cl bond in the dinitro derivative is intrinsically much weaker than in chlorobenzene, so it breaks more easily.
Steric repulsion between the nitro groups and chlorine in the dinitro compound forces chlorine out, facilitating substitution.
Methoxide reacts via a radical chain with the dinitro compound but not with chlorobenzene.
The nitro groups strongly withdraw electron density and stabilize the negatively charged Meisenheimer (σ) intermediate formed on nucleophilic addition, lowering the activation barrier for the addition–elimination pathway.
Q10. For solvolysis in ethanol at , the activation energy for ionization of benzyl chloride is lower than that for n-propyl chloride. Assuming identical pre‑exponential factors, estimate the ratio at (use ). Choose the nearest value.
Q11. Among the following haloalkanes, which will undergo nucleophilic substitution (SN2) most rapidly with hydroxide ion in acetone at K?
(1‑bromopropane)
(2‑bromopropane)
(methyl bromide)
(tert‑butyl bromide)
Q12. Which of the following will undergo nucleophilic aromatic substitution (addition–elimination, SNAr) most readily with methoxide in DMSO, taking into account resonance and inductive effects?
‑NO‑CHCl\ (‑nitrochlorobenzene)
\ (chlorobenzene)
‑NO‑CHCl\ (‑nitrochlorobenzene)
‑OCH‑CHCl\ (‑methoxychlorobenzene)
Q13. When ‑bromobutane () is treated with potassium tert‑butoxide (‑BuOK) in tert‑butanol at , which alkene will be formed predominantly?
trans‑2‑butene (‑)
cis‑2‑butene (‑)
an approximately equal mixture of cis‑ and trans‑2‑butene
1‑butene ()
Q14. Consider the following two statements. Statement‑I: Chlorobenzene does not undergo nucleophilic substitution with aqueous under mild conditions, but can be converted into aniline on treatment with in liquid followed by hydrolysis. Statement‑II: Under the /liquid conditions the reaction proceeds via elimination of to give a benzyne (aryne) intermediate, which is then attacked by nucleophile to give substitution. Which option is correct?
Statement‑I is true, Statement‑II is false
Statement‑I is true and Statement‑II is true, and Statement‑II correctly explains Statement‑I
Statement‑I is false, Statement‑II is true
Both Statement‑I and Statement‑II are false
Q15. Despite the stronger – bond, ‑nitrofluorobenzene (‑NO‑CHF) often reacts faster with methoxide (SNAr, addition–elimination) than ‑nitrochlorobenzene. Which of the following best explains this observation?
The – bond is weaker than the – bond, so departs more easily
Fluoride is a better nucleophile than chloride, which accelerates the substitution of the aryl halide
In SNAr the rate‑determining step is nucleophilic addition to form the Meisenheimer complex; the strong effect of increases ring electron deficiency and better stabilizes the intermediate, so ‑nitrofluorobenzene reacts faster
Methoxide forms stronger hydrogen bonds with fluoride in the transition state, lowering the activation energy
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